Q.38. Ammeter reading in the given circuit will be 3 Ω 3 Ω 3 Ω 3 Ω 1 Ω 2 Ω + HE A 12 Ω (α) 2 Α (6) 1A (c) 1.5A (d) 0.5 A.
Answers
Answered by
1
Answer:
(a)As all the resistances are in parallel the voltage across each of them will be same =12V
I
1
=
R
1
V
=
5
12
=2.4A
I
2
=
R
2
V
=
10
12
=1.2A
I
3
=
R
3
V
=
30
12
=0.4A
(b) Total current= I
1
+I
2
+I
3
=2.4+1.2+0.4=4A
(c) Total circuit resistance =
Total current
V
=
4
12
=3Ω
Explanation:
Answered by
1
Answer:
Labelling each of the resistance as shown in the figure below.
Resistance R₁ and R₂ are in series
⇒ R$1= R₁ + R₂
⇒ R$1 = 3 + 3 = 6 Ω
Now R1 and R3 are in parallel.
1 Rp 1 1 + R$1 R3
1 Rp 1 1 + 6 3 介
介 1 Rp 1+2 6 3 36
6 3 ⇒Rp = 2
⇒ Rp = 20
Now R4, Rp and R5 are in series.
⇒ Req = R4 + R5 + Rp
Explanation:
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