Math, asked by singhrustam100dd, 7 months ago

Q.39 A rectangular photograph is 42 cm. long and 19 cm. broad. What length of the
wooden frame would be needed for framing it? What will be the cost of the frame if
one meter of the wood cost rupee one
Q.40 Length of a room is twice its width. If length of the room is 30 meter find its area?​

Answers

Answered by NetraJ7
1

Answer:

(a) Perimeter = Sum of all the sides

= 4 cm + 2 cm + 1 cm + 5 cm = 12 cm

(b) Perimeter = Sum of all the sides

= 23 cm + 35 cm + 40 cm + 35 cm = 133 cm

(c) Perimeter = Sum of all the sides

= 15 cm + 15 cm + 15 cm + 15 cm = 60 cm

(d) Perimeter = Sum of all the sides

= 4 cm + 4 cm + 4 cm + 4 cm + 4 cm = 20 cm

(e) Perimeter = Sum of all the sides

= 1 cm + 4 cm + 0.5 cm + 2.5 cm + 2.5 cm + 0.5 cm + 4 cm = 15 cm

(f) Perimeter = Sum of all the sides

= 4 cm + 1 cm + 3 cm + 2 cm + 3 cm + 4 cm + 1 cm + 3 cm + 2 cm + 3 cm + 4 cm +

1 cm + 3 cm + 2 cm + 3 cm + 4 cm + 1 cm + 3 cm + 2 cm + 3 cm = 52 cm

Question 2:

The lid of a rectangular box of sides 40 cm by 10 cm is sealed all round with tape. What is the length of the tape required?

Answer:

Total length of tape required = Perimeter of rectangle

= 2(length + breadth)

= 2(40 + 10)

= 2 * 50

= 100 cm

= 1 m {Since 1 m = 100 cm}

Thus, the total length of tape required is 100 cm or 1 m.

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