Q 39 A refrigerator is designed to
release 750 calories of heat per
second. If the range of its
operation is 5 degree Celsius to
25 degree Celsius, then its
power is:
Ops: A.
226 W
B.
250 W
C.
300 W
D.
330 W
Answers
Answered by
14
The power is 53.95 W
Explanation:
The coefficient of performance of refrigerator is given by the formula:
COP = Tc/(Th - Tc)
Where,
Tc = Low temperature = 5°C = 278 K
Th = High temperature = 25°C = 298 K
On substituting the values, we get,
COP = 278/(298 - 278)
∴ COP = 278/20
Now, the power is given by the formula:
COP = (Desired effect)/Input
Desired effect = 750 calories of heat per second = 750 J
On substituting the values, we get,
278/20 = 750/Input
∴ Input = 53.95 J/s = 53.95 W = Power consumed by the refrigerator
Answered by
0
Answer:
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