Question

Q 39 A refrigerator is designed to
release 750 calories of heat per
second. If the range of its
operation is 5 degree Celsius to
25 degree Celsius, then its
power is:
Ops: A.
226 W
B.
250 W
C.
300 W
D.
330 W​

Answer 1

The power is 53.95 W

Explanation:

The coefficient of performance of refrigerator is given by the formula:

COP = Tc/(Th - Tc)

Where,

Tc = Low temperature = 5°C = 278 K

Th = High temperature = 25°C = 298 K

On substituting the values, we get,

COP = 278/(298 - 278)

∴ COP = 278/20

Now, the power is given by the formula:

COP = (Desired effect)/Input

Desired effect = 750 calories of heat per  second = 750 J

On substituting the values, we get,

278/20 = 750/Input

∴ Input = 53.95 J/s = 53.95 W = Power consumed by the refrigerator

Answer 2

Answer:

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