Question

Q. 39. The perimeter of a rectangle is 52 cm where length is 6 cm more then its breadth then dimension of rectangle is

2 points

16 cm & 12 cm

26 cm & 20 cm

18 cm & 12 cm

16 cm & 10 cm

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Answer 1

$\sf{\underline{\boxed{\large{\blue{\mathsf{Solution}}}}}}$

$\sf{\bold{\green{\underline{\underline{Given}}}}}$

• Perimeter = 52cm
• length is 6cm more than breadth .

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$\sf{\bold{\green{\underline{\underline{To\:Find}}}}}$

• Length and breadth = ??

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$\sf{\bold{\green{\underline{\underline{Solution}}}}}$

• Let breadth be x
• length = x + 6

$\sf{\red{\boxed{\bold{perimeter = 2( length + breadth)}}}}$

⠀⠀⠀⠀

$\sf: \implies \:{\bold{ 52 = 2( x + x + 6)}}$

⠀⠀⠀⠀

$\sf: \implies \:{\bold{ 52 = 2( 2x+ 6)}}$

⠀⠀

$\sf: \implies \:{\bold{ \dfrac{52}{2} = 2x + 6}}$

⠀⠀⠀⠀

$\sf: \implies \:{\bold{ 26 = 2x + 6}}$

⠀⠀⠀⠀

$\sf: \implies \:{\bold{2x = 26 - 6}}$

⠀⠀⠀⠀

$\sf: \implies \:{\bold{ 2x = 20cm}}$

⠀⠀⠀⠀

$\sf: \implies \:{\bold{ x = 10cm}}$

⠀⠀

$\sf{\orange{\boxed{\bold{x = breadth = 10cm}}}}$

⠀⠀⠀⠀

• Putting value of breadth to find length

$\sf: \implies \:{\bold{ 10 + 6}}$

⠀⠀⠀⠀

$\sf: \implies \:{\bold{ 16 c.}}$

⠀⠀⠀⠀

$\sf{\orange{\boxed{\bold{length = 16cm}}}}$

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$\sf{\bold{\green{\underline{\underline{Answer}}}}}$

• Length and Breadth = 10cm and 16cm = option D