Question

Q. 3a) Use source transformation technique to find the current through the 2-ohm resistor in Fig below ​

Answer 1

Answer:

0.625 A

Explanation:

Answer 2

The current through the 2 Ω resistor is 3.6 A

According to the figure,

Total current through the circuit = 20 A

Current through the extreme right branch = 8 A

∴ Amount of total current through the other two branches = (20 - 8) A

                                                                                                = 12 A

Now, the series combination of 2 Ω and 5 Ω resistor is in parallel combination with 3 Ω of resistor.

∴ The equivalent resistor of the series combination = (2+5) Ω

                                                                                      = 7 Ω

As we know, current divides in the inverse ratio of the resistors in a parallel combination,

∴ Ratio of current flowing through 7 Ω and 3 Ω resistors is = 3 : 7

∴ Current flowing through 7 Ω resistor = ( $\frac{3}{3+7}$ × 12) A

                                                                = 3.6 A

As we know, in a series combination current remains same,

∴ The current through 2 Ω resistor will be 3.6 A.