Question

Q 4/60 If in a vernier callipers 5 VSD coincides
with 4 MSD, then least count of vernier calliper is
(given 1 MSD = 1 mm)?
O 0.1 mm
O 0.4 mm
0.0.3 mm
O 0.2 mm

Answer 1

Given :

Number of vernier scale divisions = 5

Number of main scale divisions = 4

To find :

The least count of the vernier callipers

Solution :

• The least count of the vernier callipers is the difference between one smallest reading on the main scale and the smallest reading on vernier scale

• The least count of the vernier callipers is given by the formula

            $L.C = \frac{MSD}{No\:of\:VSD}$

• By substituting the values in the above formula

            $L.C=\frac{1mm}{5}$

            $L.C=0.2mm$

The least count of the vernier callipers is 0.2 m