Q#4 A particle in simple harmonic
motion is at rest at a distance of 6 cm
from it in equilibrium position at time
t = 0. Its period is 2 s. Write
expressions for its position, its
velocity v and its acceleration as a
functions of time Show your work (4
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Time period=2s
Therefore, angular frequency=2*pi/T=pi rad/s
Since, at t=0 the body is at rest at the extreme point, therefore, x=6cos(pi*t) cm at t=t s
v=v(max) sin(pi*t) cm/s=6*pi*sin(pi*t) cm/s
a=-6(pi^2)*cos(pi*t) cm/s^2
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Therefore, angular frequency=2*pi/T=pi rad/s
Since, at t=0 the body is at rest at the extreme point, therefore, x=6cos(pi*t) cm at t=t s
v=v(max) sin(pi*t) cm/s=6*pi*sin(pi*t) cm/s
a=-6(pi^2)*cos(pi*t) cm/s^2
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