Question

Q.4 A projectile is fired a velocity of 150 m/s at an angle of 30° with the horizontal. What
is the magnitude of the vertical component of the velocity at the time the project is
Fired?
(a) 225 m/s (b) 75 m/s (C) 150 m/s
(d) 130 m/s
To
off​

Answer 1

Refer to the attachment please

Answer 2

Option B is correct.

Step-by-step explanation:

Velocity ( u ) = 150 $\frac{m}{sec}$

Angle $\theta$ = 30°

Horizontal component of velocity = $u \cos \theta$

Vertical component is = $u \sin\theta$

Vertical component is = 150 × $\sin30$°

Vertical component = 150 × $\frac{1}{2}$ = 75 $\frac{m}{sec}$

Thus option B is correct.