Question

Q.4 (A) Two point charges of+5x10-1°C and +10x10-1°C
are separated by a distance of Im. At which point on the
line joining them is the electric field intensity zero. ​

Answer 1

Explanation:

Given q

1

=5×10

−19

C and q

2

=20×10

−19

C with r=2m

Suppose at a point x meter away from q_1 the field is zero then at that point the field due to individual charges should be equal and opposite

x

2

q

1

=

(2−x)

2

q

2

which lead us to x=2/3 meter from charge 5×10

−19

C

Answer 2

Answer:

35

Explanation:

36847+6866+48+47+48+858+585