Math, asked by huatti, 7 months ago

Q.4. Ankit tells his daughter, “Ten years ago, I was seven times as old as you were then.
Also, five ye ars from now, I shall be four times as old as you will be."​

Answers

Answered by MagicalBeast
0

Answer:

Ankit's age = 115 years

daughter's age = 25 years

Step-by-step explanation:

present age of daughter ,let ,x

present age of ankit = y ,let

10 year ago

(y-10) = 7(x-10)

=> y - 10 = 7x - 70

=> y = 7x - 60 ......1

5 years from now,

(y+5) = 4(x+5)

putting value of y from equation 1

we get

(7x-60) + 5 = 4x + 20

=> 7x - 4x = 20+60-5

=> 3x = 75

=> x = 75/3

=> x = 25

y = 7x - 60 = 7(25) -60

y = 175-60

=> y = 110

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