Question

Q 4. Calculate the vapour density of Sulphur dioxide (SO2 ).

Q.5. Calculate the percentage composition of Potassium chlorate (KClO3).

Answer 1

Vapour density = molar mass divided by 2
% composition = mass of element multiplied by 100/ Molar mass it gives you 31.83

Answer 2

Vapor density of Sulphur dioxide $(SO_2)$

To calculate the vapor density of the given substance, the following formula must be used

Vapour density = $\frac{Molecular weight}{2}$

The molecular weight of $SO_2$ is 64.07g/mol.

When this is substituted in the vapor density formula it gives

Vapour density of $SO_2$$= \frac{64.07}{2}$ = 32.035

Percentage composition of Potassium Chlorate ($KClO_3$)

The elements present in the given substance is 1 atom of Potassium, 1 atom of chlorine and 3 atoms of oxygen. The the molar mass of $KClO_3$

Molar mass of $KClO_3$ = 39.0983+35.4453+(15.9994*3) = 122.5495g/mol

Formula to calculate mass percentage = $\frac{Mass of a components}{Total mass of the substance}\times 100$

∴ Percentage composition of Potassium chlorate ($KCl_3$) is

Potassium = $\frac{39.0983}{122.5495}\times 100 = 31.904$%

Chlorine = $\frac{35.453}{122.5495}\times 100=28.930$%

Oxygen = $\frac{(15.9994\times 3)}{122.5495}\times 100 = 39.166$%

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