Question

Q:4)Draw two carbon compounds for following functional groups
Aldehyde
Ketone
Carboxylic acid
Alkene​

Answer 1

Explanation:

For Aldehyde

1) CH3-CH2-CHO=Propanal.

2)CH3-CH2-CH2-CHO=Butanal.

For Ketone

1)CH3-CO-CH3=Propanone.

2)CH3-CO-CH2-CH3=Butanone.

For Carboxylic group

1)CH3-COOH=Ethanoic acid.

2)CH3-CH2-COOH=Propanoic acid.

For Alkene

1)CH2=CH2 :- Ethene.

2)CH2=CH-CH3 :- Propene