Question

Q : 4 Explain the following process/events.

Put two to three iron nails in the blue solution of copper sulphate and after 15 to 20

minutes the colour of the solution turns green.

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Answer 1

Answer:

Fe(s)+CuSO4⟶Cu(s)+FeSO4

When an iron nail is dipped in copper sulphate solution, a brown coating of copper is formed on the surface of iron and the colour of copper sulphate solution changes from blue to light green. This reaction shows that iron is more reactive than copper as it displaces copper from its solution and iron passes into solution as Fe

2+ions and ferrous sulphate solution is formed.

Explanation:

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Answer 2

Answer:

Iron is a reactive metal so Iron replace copper and become iron sulphate . Equation :-

CuSo4 + 2Fe----------2FeSo2 + Cu

This is displacement reaction.