Question

Q.4 Factorize the following:
(i) 1 - 64a3 - 12a + 48a2.​

Answer 1

Answer:

1−64a

3

−12a+48a

2

=(1)

3

−(4a)

3

−3(1)

2

(4a)+3(1)(4a)

2

Suitable identities is x

3

−y

3

−3x

2

y+3xy

2

=(x−y)

3

∴(1)

3

−(4a)

3

−3(1)

2

(4a)+3(1)(4a)

2

=(1−4a)

3

Answer 2

Step-by-step explanation:

1−64a

3

−12a+48a

2

=(1)

3

−(4a)

3

−3(1)

2

(4a)+3(1)(4a)

2

Suitable identities is x

3

−y

3

−3x

2

y+3xy

2

=(x−y)

3

∴(1)

3

−(4a)

3

−3(1)

2

(4a)+3(1)(4a)

2

=(1−4a)

3