Question

Q-4.Find a quadratic polynomial, the sum and product of whose zeroes are √3 and 1√3 respectively.​

Answer 1

$sum \: of \: zeroes \: = \sqrt{3} \\ product \: of \: zeroes = \frac{1}{ \sqrt{3} } \\ poly = > {x}^{2} - (sum \: of \: zeroes)x + product \: of \: zeroes = 0 \\ = > {x}^{2} - \sqrt{3} x + \frac{1}{3} = 0 \\ = > \sqrt{3} {x}^{2} - 3x + 1 = 0$