Question

Q.4 Find the perimeter of a rhombus whose diagonals are 16 cm and 12 cm​

Answer 1

Answer:

Given:

• Diaginal,d1 = 16 cm
• Diagonal, d2 = 12 cm

To find out:

Find the perimeter of a rhombus.

Solution:

We know diagonal of a rhombus bisect each other at right angles.

AC = 16 cm, OC = 1/2 AC => 1/2 x 16 = 8 cm

BD = 12cm, OD = 1/2 BD => 1/2 x 12 = 6 cm

By using pythagoras theorem:

DC² = OC² + OD²

DC² = 8² + 6²

DC² = 64 + 36

DC² = 100

DC² = 10 cm

Therefore,

DC = BC = AD = AB = 10 cm [ All sides are equal ]

Now,

Perimeter of rhombus = 4 ( side)

= 4 x 10

= 40 cm

I hope this will be help you.