Q.4 Find the solution of 2x² - 5x - 3 = 0
Answers
Answered by
2
Answer:
2x
2
−5x−3
2 {x}^{2} - 6x + x - 32x
2
−6x+x−3
2x(x - 3) + 1( x - 3)2x(x−3)+1(x−3)
(2x+ 1)(x - 3)(2x+1)(x−3)
x = - \frac{1}{2} \: and \: x = 3x=−
2
1
andx=3
Answered by
0
Answer:
2x²-5x-3=0
2x²- 6x+ x-3 =0
2x(x-3 ) + 1 ( x-3 ) =0
(x-3) (2x+1) =0
x=3, ½
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