Question

Q.4 Find the solution of 2x² - 5x - 3 = 0
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Answer 1

Answer:

2x

2

−5x−3

2 {x}^{2} - 6x + x - 32x

2

−6x+x−3

2x(x - 3) + 1( x - 3)2x(x−3)+1(x−3)

(2x+ 1)(x - 3)(2x+1)(x−3)

x = - \frac{1}{2} \: and \: x = 3x=−

2

1

andx=3

Answer 2

Answer:

2x²-5x-3=0

2x²- 6x+ x-3 =0

2x(x-3 ) + 1 ( x-3 ) =0

(x-3) (2x+1) =0

x=3, ½