English, asked by sharmas02333, 5 months ago

Q.4 Find the surface tension in a soap bubble of 40 mm diameter when the inside

pressure is 2.5 N/m2 above atmospheric pressure.​

Answers

Answered by Fatimakincsem
5

The surface tension on the bubble is σ  = 0.0125 N/m

Explanation:

We are given that:

  • Diameter of soap bubble = 40 mm = 40 x 10^-3 m
  • Inside pressure of the bubble = 2.5 N/m^2
  • To Find: Surface tension = "σ" = ?

Solution:

The formula to find tension is given below;

Pressure = 8 x σ / d

2.5  = 8 x σ / 40 x 10^-3

σ  = 40 x 10^-3 x 2.5 / 8

σ  = 100 x 10^-3 / 8

σ  = 100 / 8000

σ  = 0.0125 N/m

Thus the surface tension on the bubble is σ  = 0.0125 N/m

Answered by deepakkumarbais
0

Answer:

0.0817

0.0546

0.975

0.635

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