Question

Q.4 Heat is being supplied at a constant rate to a sphere of ice which is melting at the rate of 0.1 gm see. It
melts completely in 100 sec. The rate of rise of temperature thereafter will be
(Assume no loss of hest.)
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Answer 1

Answer:

Explanation:

Given the melting rate and the time taken to melt the entire mass of ice, we can get the mass of the block of ice.

Rate = 0.1 gram per second

Time taken to melt the ice = 100seconds.

Mass of ice = 0.1 × 100 = 10 g

Heat absorbed by the ice = mLf

Where m is the mass of ice and Lf the latent heat of fusion of ice.

Lf = 334000Joules per Kg

Convert the mass to kg:

10 / 1000 = 0.01 Kg

Substituting the values into the formula we have :

0.01 × 334000 = 3340 Joules.

The heat required to melt the block of ice is thus 3340 Joules.