Question

Q(4) if 10^-10 electros move out of a body to another body every second, how much time is required to get a total charge of 1C on the other body?​

Answer 1

Answer:

Total charge transferred in 1 s

$= {10}^{10} \times 1.6 \times {10}^{ - 19} = 1.6 \times {10}^{ - 9} c \\ \\so \: time \: taken \: it \: to \: reach \: 1 \: c \\ \\ = \frac{1}{1.6 \times {10}^{ - 9} } \: s \\ \\ = \frac{5}{8} \times {10}^{9} \: s$