Q.4 If an object of mass 7 kg is accelerated
uniformly at the rate of 10 m/s2. Then find
the force exerted on that object. If the
same force is applied on another object of
mass 36 kg then how much acceleration
the object will gain?
Answers
Answered by
11
Explanation :
QUESTION NO. 1
Given :
- Mass of object = 7 kg
- Acceleration = 10 m/s²
To find :
- Force exerted on object
Here,
□ Mass of object (m) = 7 kg
□ Acceleration (a) = 10 ms-²
Now we will use Newton's 2nd law :
⇒ Force exerted (F) = m × a
Substituting values,
⇒ F = 7 × 10
⇒ F = 70
⇒ F = 70 N
∴ Force exerted on object = 70 N (1)
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QUESTION NO.2
Given :
- Mass of 2nd object = 36 kg
- Force applied = 70 N [∵F = F' = 70 N]
To find :
- Acceleration of 2nd object
Here,
□ Mass of object (m) = 36 kg
□ Force applied = 70 N
We will use Newton's 2nd law here :-
⇒ Force = Mass × Acceleration
Substituting values,
⇒ 70 = 36 × a
⇒ 36a = 70
⇒ a = 70/36
⇒ a = 1.94 m/s²
∴ Acceleration of object = 1.94 ms-² (2)
Answered by
14
QUESTIONS:
- If an object of mass 7kg is accelerated uniformly 10 m/s² . The find the force applied on that object
- If the same force acted on the other block of mass 36kg . Then how much acceleration will be produced
SOLUTION 1:
Given
- Mass of object = 7kg
- Acceleration = 10 m/s²
Using the Newton's law of motion
F = m × a
Where
- F : Force = ?
- m : mass = 7kg
- a : acceleration = 10 m/s²
Substituting the values we have
→ F = 7 × 10
→ F = 70N
SOLUTION 2:
The same force is acting on the object of mass 36kg
Given
- Force acting = 70N
- Mass of object = 36 kg
Using Newton's law of motion
F = m × a
Simplifying
a = F/m
→ a = 70/36
→ a = 1.94 m/s²
Hence, acceleration produced = 1.94m/s²
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