Physics, asked by deepanshukumar74, 8 months ago

Q.4 If an object of mass 7 kg is accelerated
uniformly at the rate of 10 m/s2. Then find
the force exerted on that object. If the
same force is applied on another object of
mass 36 kg then how much acceleration
the object will gain?​

Answers

Answered by EliteSoul
11

Explanation :

QUESTION NO. 1

Given :

  • Mass of object = 7 kg
  • Acceleration = 10 m/s²

To find :

  • Force exerted on object

Here,

□ Mass of object (m) = 7 kg

□ Acceleration (a) = 10 ms-²

Now we will use Newton's 2nd law :

Force exerted (F) = m × a

Substituting values,

⇒ F = 7 × 10

⇒ F = 70

F = 70 N

Force exerted on object = 70 N (1)

___________________________

___________________________

QUESTION NO.2

Given :

  • Mass of 2nd object = 36 kg
  • Force applied = 70 N [∵F = F' = 70 N]

To find :

  • Acceleration of 2nd object

Here,

□ Mass of object (m) = 36 kg

□ Force applied = 70 N

We will use Newton's 2nd law here :-

⇒ Force = Mass × Acceleration

Substituting values,

⇒ 70 = 36 × a

⇒ 36a = 70

⇒ a = 70/36

a = 1.94 m/s²

Acceleration of object = 1.94 ms-² (2)

Answered by ItzArchimedes
14

QUESTIONS:

  1. If an object of mass 7kg is accelerated uniformly 10 m/s² . The find the force applied on that object
  2. If the same force acted on the other block of mass 36kg . Then how much acceleration will be produced

SOLUTION 1:

Given

  • Mass of object = 7kg
  • Acceleration = 10 m/s²

Using the Newton's law of motion

F = m × a

Where

  • F : Force = ?
  • m : mass = 7kg
  • a : acceleration = 10 m/s²

Substituting the values we have

→ F = 7 × 10

→ F = 70N

SOLUTION 2:

The same force is acting on the object of mass 36kg

Given

  • Force acting = 70N
  • Mass of object = 36 kg

Using Newton's law of motion

F = m × a

Simplifying

a = F/m

→ a = 70/36

→ a = 1.94 m/s²

Hence, acceleration produced = 1.94m/

Similar questions