Q.4) If x + y = 12, xy = 14; find the value of ((x2 + y²)
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The value of (x^2 + y²) is equal to 116.
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Step bu Step explanation
Given x+y=12 ---(1)
xy = 14 ------(2)
On Squaring both sides of equation (1) ,we get
(x+y)²= 12²
=> x²+2xy+y² = 144
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=> x²+y² +2×14=144
/* From (2)*/
=> x²+y²+28 = 144
=> x²+y² = 144-28
=> x²+y² = 116
Therefore
x²+y² = 116
Hoping I helped you out ..
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