Question

Q.4. In the figure M is the midpoint of QR. ZPRQ = 90°.
Prove that POʻ = 4PM²-3PR²​

Answer 1

Answer:

Step-by-step explanation:

Let MR=MQ=x and PR=y

then in Δ PRM

PM²=x²+y²

Again in Δ PRQ

PQ²=y²+QR²

=y²+(x+x)²

=PM²-x²+4x²

=PM²+3x²

=PM²+3(PM²-y²)

=PM²+3PM²-3y²

=4PM²-3y²

PQ²=4PM²-3PR²