Q.4 In the given fig, find the value of a+b
128°
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a
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∠ABP=85(Given)
∠AOB=2(∠ABP)(Angleincribedbycentreofcircleisdoubleangleinscribedbyanychord)
∠AOB=2×85=170
In△AOB
SinceOA=OB(Oiscentreofcircle)
∠OAB=∠OBA(Anglealongtheequalsideareequal)
Hence∠OAB+∠OBA+∠AOB=180
∠OAB+∠OBA=180−170=10
Hence∠OAB=∠OBA=5
∠OAB=a=5
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