Q 4 plz with steps
request First to answer will be brainiest
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let no be x nd y
then x + y=16
or, y= 16-x
again, (2x)^2 -y^2=164
4x^2-y^2=164
4x^2-(16-x)^2=164
4x^2-{(16)^2+x^2- 32x}=164
4x^2-x^2+32x= 164+256
3x^2+32x-420=0
solve kr lio aage bhai
then x + y=16
or, y= 16-x
again, (2x)^2 -y^2=164
4x^2-y^2=164
4x^2-(16-x)^2=164
4x^2-{(16)^2+x^2- 32x}=164
4x^2-x^2+32x= 164+256
3x^2+32x-420=0
solve kr lio aage bhai
tonylee:
nice try bro but actual answer is x^2+32x-420
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