Question

Q 4. Prove that the Ilgm circumscribing a
circle is a rhombus.​

Answer 1

Answer:

Given ABCD is a ||gm such that its sides touch a circle with centre O. We know that, tangents to a circle from an exterior point are equal in length. Hence, ABCD is a rhombus. ... If they are equal, then rhombus is considered as a square whose diagonals are always equal

Answer 2

Given ABCD is a ||gm such that its sides touch a circle with centre O. We know that, tangents to a circle from an exterior point are equal in length. Hence, ABCD is a rhombus.

Mark my answer as brilliant