Q.4. Razor blades are supplied by a manufacturing company in packets of
10.there is a probability of 1 in 100 blades to be defective.Calculate the number
of packets containing one defective blade, no defective blade, no defective
blade and all defective blade in a consignment of 10,000 packets.
Answers
Answer:
1000blade detect and 9000un defects
Answer:
The probability of a defect per blade is p = 1/500 = 0.002. This means that for a packet of 10, the mean
number of defects L = 10p = 0.02. The parameter L is used in the Poisson distribution to give the probability
of the number of defects, n, in a packet of 10:
() =L^n/! *e^-L
(0)=0.02^0/0!*e^-0.022 ≈ 0.98;
The approximate number of packets containing blades with no defective blades is (0) ∗ 10000 ≈ 9800
(1) =0.02^1/1!*e^-0.02≈ 0.0196;
The approximate number of packets containing blades with one defective blade is (1) ∗ 10000 ≈ 196
(2) =0.02^2/2!*e^-0.022 ≈ 0.000196;
The approximate number of packets containing blades with two defective blades is (2) ∗ 10000 ≈ 2
(3) =0.02^3/3!*e^-0.022 ≈ 0.0000013;
The approximate number of packets containing blades with three defective blades is (3) ∗ 10000 ≈ 0
therefore sollution is: 9800; 196; 2; 0.