Question

Q.4
Solve the following. (Any 2)
1) Find the median and mode of the following data.
Class (Rs.)
300-309 310-319 320-329 330-339 340-349 350-359
Frequency of
No. of students.
20
24
38
48
27​

Answer 1

Solution:

• From the given data we can find that the max frequency is $48$ and the class corresponding frequency to it is  $340-349$.
• Therefore the median is  $=340-349$
• Therefore the values here given are,

         $f_{1} =48$ ,  $f_{0} =38$,   $f_{2} =27, l=340, h=9m$

• ∴ mode can be found by using the formula,

           $m=l+\frac{f_{1}-f_{0}}{2f_{1}-f_{0}{-f_2} }(h)$

               $=340+\frac{48-38}{(2)48-38-27} (9)$

              $=340+\frac{10}{96-65} (9)$

              $=340+\frac{10}{31} (9)$

             $=340+2.9$

             $=342.9$

answer:  the median and mode are $=340-349$ and $=342.9$ respectively.

#SPJ3

Answer 2

Answer:

model class=339.5

f1=48. f2=27. f0=38

Mode= l+ f1- f0/2f1--f0-f2 ×h

= 339.5 + 48-38/ 2×48-38-27 ×10

= 339.5+ 10/96- 65 ×10

= 339.5 + 100/31

= 339.5+ 3.225

= 339.5 + 3.23

= 342.73

correct answer is 342.73 approx.