Question

Q.4 Solve the given equation:
5/7x-3 = 3/9x-5

Answer 1

$\frac{5}{7x - 3} = \frac{3}{9x - 5}$

$5(9x - 5) = 3(7x - 3)$

$45x - 25 = 21x - 9$

$45x - 21x = - 9 + 25$

$24x = 16$

$x = \frac{16}{24}$

$x = \frac{8 \times 2}{8 \times 3}$

$x = \frac{2}{3}$

$x = 0.6666666.. \infty$

Answer 2

$\large\bigstar{\pmb{\sf Solution }}$

$:\implies\sf\dfrac{5}{7x-3} = \dfrac{3}{9x-5}$

$:\implies \sf 5(9x-5)=3(7x-3)$

$:\implies\sf 45x-25=21x-9$

$:\implies \sf 45x-21x=25-9$

$:\implies\sf 24x=16$

$:\implies \sf x=\dfrac{16}{24} =\bf\red{\dfrac{2}{3} }$

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I hope its beneficial :D