Question

Q. 4) The perpendicular distance between form the point (3,4)to the line 2x + 6y + 70 & 2x + y + 5=0
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Answer 1

Step-by-step explanation:

perpendicular distance between (3,4) and 2x+6y +70

d= 2×3+6×4+70/ √2^2+6^2

= 6+24+70/ √40

= 100/2√10 unit

=50/√10 unit .

perpendicular distance between (3,4) and 2x +y +5 =0

d = 6+4 +5 / √4+1

= 15/√5

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