Q(4) The population of a certain town was 50,000. In a year, male population was increased
by 5% and female population was increased by 3%. Now the population became
52020. Then what was the number of males and females in the previous year?
Answers
Answered by
3
- Male = 26000
- Female = 24000
⠀─────────────────────
⠀
★ Given
- Initially the population town is 50000.
⠀
let the population of male and female of previous year be x and y respectively.
- x + y = 50000
- Female = y
- Male = x = 50000 – y. Equation ❶
⠀
It is given that the male population increased by 5% and female population has increased by 3% so the increase in population is,
⠀
⠀
⠀
★ Now,
Putting Equation ❶ with Equation ❷.
Multiply 105 by Equation ❶ and Subtract it from ❷, we get
➥ The number of female = y = 24000
Now, we have the value of y i.e., 24000 and now let us find the value of x.
According to Equation ❶
∴ The number of male and female in previous year was 2400 and 2600 respectively.
Similar questions