Math, asked by artig6289, 4 months ago

Q. 4. The sides of a polygon are 8 in numbers
what would be the sum of its internal angles ?​

Answers

Answered by saumyabrijeshmehta
0

Answer:

(n−2) × 180

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Answered by poojadevi4
0

Answer:

We will learn how to find the sum of the interior angles of a polygon having n sides.

We know that if a polygon has ‘n’ sides, then it is divided into (n – 2) triangles.

We also know that, the sum of the angles of a triangle = 180°.

Therefore, the sum of the angles of (n – 2) triangles = 180 × (n – 2)

= 2 right angles × (n – 2)

= 2(n – 2) right angles

= (2n – 4) right angles

Therefore, the sum of interior angles of a polygon having n sides is (2n – 4) right angles.

Thus, each interior angle of the polygon = (2n – 4)/n right angles.

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