Question

Q.4
The velocity of electron in third excited state of
Be3+ will be -
(1) (2.188 X10%) ms-1
Alw Alw
(2) (2.188 x106) ms-1
(3) (2.188 106) Kms-
(4) (2.188 x 103) Kms-​

Answer 1

hey mate.....☺️☺️☺️☺️

here's your answer..

V=(2.188×10^6) × Z/n m/s

=(2.188×10^6) × 4/4 m/s

=(2.188×10^6) m/s

Brain list pls❤️❤️❤️

@toshika

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