Question

Q 4. The velocity-time graphs of a car and a scooter are shown in the figure. (i) The difference between the distance travelled by the car and the scooter in 15 s and (ii) the time at which the car will catch up with the scooter are, respectively.
(1) 112.5 m and 15 s
(2) 337.5 m and 25 s
(3) 112.5 m and 22.5 s
(4) 225.5 m and 10 s

Answer 1

Answer:

Correct option is

C

112.5m and 22.5s

The distance traveled in 15 seconds by both will be given by area under curve.

For car, s

1

=

2

1

×15×45

s

1

=337.5m

For scooter, s

2

=15×30

s

2

=450

s

1

−s

2

=112.5m

Suppose after time t, they will meet, then distance traveled by both of them will be equal.

30t=

2

1

×15×45+45×(t−15)

30t=337.5+45t−675

15t=337.5

t=22.5s

(Pls Mark me brainlist plsss I request)