English, asked by harsah, 11 months ago

Q.4] Three coins are tossed together. Find the probability of getting:
(i) exactly two heads
(ii) at least two heads
(iii) at least one head and one tail. (iv) no tails​

Answers

Answered by Lightingboy
0

Answer:

can you tell what direction it kept

Explanation:

I think 3

Answered by Swetha02
8

Hey buddy,

Here's your answer ⤵️⤵️⤵️

If three different coins tossed together,  the total possible outcomes are TTT, TTH, THT, THH, HTT, HTH, HHT\:and \:HHH.

Number of total possible outcomes  = 8\longrightarrow(1)

(i) Let the event exactly two heads be "E"

Favorable outcomes = TTH, THT, HTT

Number of favorable outcomes = 3

Now,  P(E)=\frac{2}{1}

= \frac{3}{8}

(ii) Let the event is at least two  heads is "E

Number of favorable  outcomes = 4\longrightarrow(3)

P(E) = \frac{3}{1}

=\frac{4}{8}

=\frac{1}{2}

Hope it helps ☺️    

-Shruthi ❤️

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