Question

ᴘʟᴇᴀꜱᴇ ᴀɴʏᴏɴᴇ ꜱᴏʟᴠᴇ ᴛʜɪꜱ Qᴜᴇꜱᴛɪᴏɴ

ᴅᴏɴ'ᴛ ꜱᴘᴀᴍ​

Answer 1

$\bf\huge\underline{\underline{ Given :- }}$

• $\bf m_{1} = 500 g$

• $\bf u_{1} = 200cm/s$

• $\bf m_{2} = 100 g$

• $\bf u_{2} = 100 cm/s$

• they collides each other

• after collision they stick together

$\bf\huge\underline{\underline{ To \: Find:- }}$

• final velocities of spheres

• Loss of Kinetic Energy

$\bf\huge\underline{\underline{ Answer :- }}$

According to Law of Conservation of Momentum ,

• $\bf m_{1}u_{1} +m_{2}u_{2} = m_{1}v_{1} + m_{2}v_{2}$

• $\bf v = v_{1} = v_{2}$ Beacuse they stick together and have common velocity

• $\bf v = \frac{m_{1}u_{1} +m_{2}u_{2}}{m_{1} + m_{2} }$

• $\bf\red{v = \frac{500×200 + 100×(-100) }{500+100} = 150 cm/s }$

$\rule{10cm}{0.05cm}$

• $\bf ∆E = \frac{m_{1}m_{2}}{2(m_{1}+m_{2})} (u_{1}²-u_{2}² )$

• $\bf ∆E = \frac{500×100}{2(500+100)} (200²-(-100)²)$

• $\bf\red{ ∆E = 3.75×10^{6} erg}$

$\rule{10cm}{0.05cm}$

• Final velocity = 150 cm/s

• Loss of Kinetic Energy = 3.75 ×10⁶ erg

Answer 2

Answer:

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