Question

Q. 42: A completes certain work in 20 days. B can do th of
same work in 3 days, C is twice efficient than B. If they work
together, then in how many days they will complete the work?
A) 10 B) 15 097 D) 10-
i​

Answer 1

Answer:

Work is completed in 0.95 days if A, B and C work together

Step-by-step explanation:

A can complete work in 20 days

B can complete work in 3 days

Also, C is twice efficient than B

Thus, C complete work in $\frac{3}{2}$ days

A's one day work $=\frac{1}{20}$

B's one day work $=\frac{1}{3}$

C's one day work $=\frac{2}{3}$

Total work is LCM of (20, 3 and 3) $=60\hspace{0.1cm}parts$

A's one day work $=3\hspace{0.1cm}parts$

B's one day work $=20\hspace{0.1cm}parts$

C's one day work $=40\hspace{0.1cm}parts$

(A + B + C)'s 1 day work $=63\hspace{0.1cm}parts$

63 parts of work takes 1 day

60 parts of work takes $\frac{60}{63} = 0.95 days$