Question

Q.43 If the equation (a^2 +b^2) x^2 -2 (ac + bd) x +c^2+ d^2 = 0 has equal roots, then :
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Answer 1

Step-by-step explanation:

roots are equal .so

{-2(ac+bd)}^2=4(a^2+b^2)(c^2+d^2)

4(a^2c^2+b^2d^2+2abcd)=4(a^2c^2+b^2c^2+a^2d^2+b^2d^2)

2abcd,=b^2c^2+a^2d^2

b^2c^2+a^2d^2-2abcd=0

(bc-ad)^2=0

bc-ad=0

bc=ad