Q.43. The radius of curvature of meter gauge railway
line at a place where the train is moving with a
speed of 10 m/s is 50 m. If there is no side thrust
on the rails, find the elevation of the outer rail
above the inner rail.
Solution:
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Answer:
Nsinθ=
r
mv
2
Ncosθ=mg
tanθ=
rg
v
2
if we define h as the elevation,
1.5
h
=
1000×9.8
100
h=
98
1.5
Explanation:
Hope it is helpful
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