Question

Q.43) The sum of three consecutive multiples of 3 is 45. The middle number is *


A) 12

B) 18

C) 15

D) 21​

Answer 1

Answer:

Answer:let the number be Xthen, multiples of 3 be X+X+3+X+6and there sum is 45. Answer:let the number be Xthen, multiples of 3 be X+X+3+X+6and there sum is 45. ATQ,=> X+X+3+X+6=45=> 3x+9=45=> 3x=45-9=> 3x=36=> x=36/3=> x=12thus, the multiples of 3 is 12,15 and 18and 18 is the greatest multiple among them.

Answer 2

Answer:

C) 15

Step-by-step explanation:

Let the number be Xthen, multiples of 3 be X+X+3+X+6and there sum is 45. Answer:let the number be Xthen, multiples of 3 be X+X+3+X+6and there sum is 45. ATQ,=> X+X+3+X+6=45=> 3x+9=45=> 3x=45-9=> 3x=36=> x=36/3=> x=12thus, the multiples of 3 is 12,15 and 18and 18 is the greatest multiple among them.