Question

Q.45. If the cube roots of the unity are 1, w, w^3
then the roots ofthe equation(x- 1)^3 +8=0 with full explanation please ‍♂️​

Answer 1

Step-by-step explanation:

it is given that the roots of

${x}^{3} = 1$

are 1,w,w^2.

let's take (x-1) as y hence

${y}^{3} = - 8$

roots of the above equation are -2,-2w, -2w^2 now substitute y by (x-1) then we get roots of x as 1-2,1-2w,1-2w^2 =>

-1,1-2w,1-2w^2. hope it helps you.