Question

Q. 47. Complete and balance the following ionic equations:
(i) Cu + Ag+
Cu2+ + Ag
(ii) Na + H+ → Nat + H
(ii) Sn2+ + Hg2+
Sn4+ + Hg (iv) Fe + H+ - Fe2+ + H,​

Answer 1

Answer:

(i)..2Cu+Ag>2givesCu>2+..+2Ag

(ii)..2Na+2H+gives2Na>+..+H>2

(iii)..Sn>2+2Hg>2+givesSn>4+2Hg

(iv)..4Fe+2H>+gives2Fe>2+..+h>2

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Explanation:

Answer 2

Answer:

(i)2Cu+Ag2 --->Cu2 +2Ag

(ii)2Na+ 2H--->2Na + H2

(iii)Sn2 + 2Hg2---->Sn4 + 2Hg

(iv)4Fe + 2H---->2Fe2 + H2

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