Question

Q 48/80 A rectangular glass slab of thickness
8 cm
is placed on a figure. Eye is kept exactly above
this slab. If the refractive index of glass is 1.6,
then the figure will appear to be raised by:
8cm,2.4cm,4.2cm,3cm

Answer 1

Explanation:

apparent depth = real depth /refractive index

apparent depth= 8 /1.6

= 80/16=5cm

normal shift = real depth - apparent depth

= 8-5 =3cm.