Physics, asked by khushi909237, 6 months ago


Q.48 A marble moving with a speed 0.2 m/s rolls off the edge of a table 0.8 m high. It will strike the student is able
a distance from the table
(A) 0.04 m
(B) 0.24 m
(C) 0.16 m
L (D) 0.08 m

Answers

Answered by pritiguptamumbai2808
0

Explanation:

Using h=

2

1

gt

2

, we have

h

AB

=

2

1

gt

AC

2

or t

AC

=

g

2h

AB

=

9.8

2×4

=0.9s

Further, BC=vt

AC

.

or v=

t

AC

BC

=

0.9

5.0

=5.55m/s

Answered by yashjoshi26
1

Answer:

  • the answer is 0.16 hope you like!!
Similar questions