Q.48 A marble moving with a speed 0.2 m/s rolls off the edge of a table 0.8 m high. It will strike the student is able
a distance from the table
(A) 0.04 m
(B) 0.24 m
(C) 0.16 m
L (D) 0.08 m
Answers
Answered by
0
Explanation:
Using h=
2
1
gt
2
, we have
h
AB
=
2
1
gt
AC
2
or t
AC
=
g
2h
AB
=
9.8
2×4
=0.9s
Further, BC=vt
AC
.
or v=
t
AC
BC
=
0.9
5.0
=5.55m/s
Answered by
1
Answer:
- the answer is 0.16 hope you like!!
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