Q.5 [1/(2 + V5)] can also be written as
(a) (2-75) (b) (V5 - 2) (c) [1/(2 + V5)] (d) (1 + (2 + V5)]
Answers
Answer:
(c) [1/(2+V5)]
Step-by-step explanation:
this is the only possiable way of answer
Answer:
.5 [1/(2 + V5)] can also be written as
(a) (2-75) (b) (V5 - 2) (c) [1/(2 + V5)] (d) (1 + (2 + V5
Step-by-step explanation:
ns Solutions. All Mathematics Part I Solutions Solutions for class Class 9 Math are prepared by experts and are 100% accurate.
Page No 21:
Question 1:
Classify the decimal form of the given rational numbers into terminating and non-terminating recurring type.
(i)
13
5
(ii)
2
11
(iii)
29
16
(iv)
17
125
(v)
11
6
ANSWER:
(i)
13
5
Since, 5=20×51
⇒ The denominator is in the form of 2m×5n, where m and n are non-negative integers.
So, the decimal form of
13
5
will be terminating type.
(ii)
2
11
Since, 11=20×50×111
⇒ The denominator is not in the form of 2m×5n, where m and n are non-negative integers.
So, the decimal form of
2
11
will be non-terminating recurring type.
(iii)
29
16
Since, 16=24×50
⇒ The denominator is in the form of 2m×5n, where m and n are non-negative integers.
So, the decimal form of
29
16
will be terminating type.
(iv)
17
125
Since, 125=20×53
⇒ The denominator is in the form of 2m×5n, where m and n are non-negative integers.
So, the decimal form of
17
125
will be terminating type.
(v)
11
6
Since, 6=21×50×31
⇒ The denominator is not in the form of 2m×5n, where m and n are non-negative integers.
So, the decimal form of
11
6
will be non-terminating recurring type.