Question

Q.5.12 A body travels a distance of 3 km towards East then km towards North and finally 9 km
East
(a) What is the total distance travelled?
(b) What is the resultant displacement?​

Answer 1

Answer:

(a) 12km

(b) root90

Explanation:

Answer 2

Answer:

(a) total distance travelled  = AB+BC+CA=(3+4+9)km = 16 km

(b) If we see the diagram, as ABCD is a rectangle.

AB=CD=4 km

BC=AD=9 km

OD = OA + AD=3+9=12 km

Consider right angle triangle ODC

By Pythagoras theorem,

OC²=OD²+CD²=12²+4²

=144+16

OC²=160KM

OC=√160=12.65Km

Hence displacement is 12.65 Km

HOPE THIS HELPS YOU! :)