Question

Q.5-A bag contains 30 balls number from 1 to 30. One ball is drawn at random. Then the probability that the number of ball is a multiple of 5 or 6 would be

Answer 1

Answer:

1/3

Step-by-step explanation:

Favourable outcomes = 5,6,10,12,15,18,20,24,25,30

Number of favourable outcomes = 10

Total number of possible outcomes = 30

Probability = 10/30 = 1/3

Answer 2

Total number = 30

(A) Probability of the number being multiple of 3 is

P (3, 6, 9, 12, 15, 18, 21, 24, 27,30) =

30

10

=

3

1

(B) Probability of the number being multiple of 5 is P(5, 10, 15, 20, 25, 30) =

30

6

=

5

1

=0.2

(C) Probability of the number being multiple of 7 is P (7,14, 21,28)=

30

4

=

15

1

(D) Probability of the number being multiple of 3 and 5 is P(15,30) =

30

2

=

15

1