Q.5) A Compound forms hcp structure what is the number of (a) octahedral volds, tetrahedral
voids, (c) total voids formed in 0.2 mol of the compound?
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Answer:
here you go
Explanation:
Number of close-packed particles = 0.5×6.022×1023= 3.011×1023
Therefore, number of octahedral voids = 3.011×1023
And, number of tetrahedral voids = 2×3.011×1023= 6.022×1023
Therefore, total number of voids = 3.011×1023+ 6.022×1023= 9.033×1023
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