Question

Q.5.A cricketer throws a ball at an
angle of 30° with the horizontal
having velocity 30ms-!. The maximum
height attained by the ball is(Take g =
10 ms-2) *
(a) 40.25m
O (
(b) 20.50m
O (
(c) 11.25 m
O (d) 50 m​

Answer 1

Answer:

C

Explanation:

H=u²sin²Ф÷2g

   =30×30×sin²30÷2×10

    =900÷4×20

we know that sin²30=1÷4

    =11.25 metres