Science, asked by JAPKIRAT2007, 6 hours ago

Q.5 A player runs along the boundary of a square ground of side 20 m in 80 s. If the player starts running from one of the vertices of the square, magnitude of displacement of the player at the end of 2 minutes from his initial position is-
a)40 m
b)120 m
c)80√2 m
d)20√2 m

Answers

Answered by subha2007293

Answer:

Explaination:time taken to travel 200m( perimeter of square is 4*side)=200s. i.e time taken to travel 1m is 1sec.i.e speed of player is 1m/s so The distance travelled is (1*(11*60)+40)=700m i.e 3.5 rounds of the field so displacement is AC(see in photo)=diagonal of square According to pythagorus theorem. (AD)^2+(DC)^2=(AC)^2. So AC=(2500+2500)^1/2. AC=50root2ANSWER:option D

Answered by Nikita203

Answer:

d) 20√2 m

Explanation:

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Q.5 A player runs along the boundary of a square ground of side 20 m in 80 s. If the player starts running from one of the vertices of the square, magnitude of displacement of the player at the end of 2 minutes from his initial position is- a)40 m b)120 m c)80√2 m d)20√2 m

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Q.5 A player runs along the boundary of a square ground of side 20 m in 80 s. If the player starts running from one of the vertices of the square, magnitude of displacement of the player at the end of 2 minutes from his initial position is-
a)40 m
b)120 m
c)80√2 m
d)20√2 m